Description
Table: Products
| Column Name | Type |
|---|---|
| product_id | int |
| product_name | varchar |
| product_category | varchar |
product_idis the primary key (column with unique values) for this table.- This table contains data about the company’s products.
Table: Orders
| Column Name | Type |
|---|---|
| product_id | int |
| order_date | date |
| unit | int |
- This table may have duplicate rows.
product_idis a foreign key (reference column) to the Products table.unitis the number of products ordered inorder_date.
Problem Statement
Write a solution to get the names of products that have at least 100 units ordered in February 2020 and their amount.
Return the result table in any order.
The result format is in the following example.
Example 1:
Input:
Productstable:
| product_id | product_name | product_category |
|---|---|---|
| 1 | Leetcode Solutions | Book |
| 2 | Jewels of Stringology | Book |
| 3 | HP | Laptop |
| 4 | Lenovo | Laptop |
| 5 | Leetcode Kit | T-shirt |
Orderstable:
| product_id | order_date | unit |
|---|---|---|
| 1 | 2020-02-05 | 60 |
| 1 | 2020-02-10 | 70 |
| 2 | 2020-01-18 | 30 |
| 2 | 2020-02-11 | 80 |
| 3 | 2020-02-17 | 2 |
| 3 | 2020-02-24 | 3 |
| 4 | 2020-03-01 | 20 |
| 4 | 2020-03-04 | 30 |
| 4 | 2020-03-04 | 60 |
| 5 | 2020-02-25 | 50 |
| 5 | 2020-02-27 | 50 |
| 5 | 2020-03-01 | 50 |
Output:
| product_name | unit |
|---|---|
| Leetcode Solutions | 130 |
| Leetcode Kit | 100 |
Explanation:
- Products with
product_id = 1is ordered in February a total of(60 + 70) = 130. - Products with
product_id = 2is ordered in February a total of 80. - Products with
product_id = 3is ordered in February a total of(2 + 3) = 5. - Products with
product_id = 4was not ordered in February 2020. - Products with
product_id = 5is ordered in February a total of(50 + 50) = 100.
Solution
Let’s break down the problem.
- First you need to join these two tables so that you can have information on
product_nameand the number ofunitssold.
1SELECT product_name, unit, order_date
2 FROM Products p
3 JOIN Orders o
4 ON p.product_id = o.product_id
- You also need to focus on results from February 2020. So, you need to filter the results from that month alone. You can do this by including a filter
WHERE DATE_FORMAT(order_date, '%Y-%m') = '2020-02'to the above query. - Next, you need to calculate the sum of
unitper product. This can be done using aggregation with below query.
1SELECT product_name, SUM(unit) AS unit
2 FROM Products p
3 JOIN Orders o
4 ON p.product_id = o.product_id
5 WHERE DATE_FORMAT(order_date, '%Y-%m') = '2020-02'
6 GROUP BY product_name
| product_name | unit |
|---|---|
| Leetcode Solutions | 130 |
| Jewels of Stringology | 80 |
| HP | 5 |
| Leetcode Kit | 100 |
- The last thing is to filter out the results which have
unitgreater than or equal to 100. You can include aHAVING unit >= 100clause for this.
The final query looks like this.
1SELECT product_name, SUM(unit) AS unit
2 FROM Products p
3 JOIN Orders o
4 ON p.product_id = o.product_id
5 WHERE DATE_FORMAT(order_date, '%Y-%m') = '2020-02'
6 GROUP BY product_name
7 HAVING unit >= 100;


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