Description

Table: Friendship

Column NameType
user1_idint
user2_idint
  • (user1_id, user2_id) is the primary key (combination of columns with unique values) for this table.
  • Each row of this table indicates that there is a friendship relation between user1_id and user2_id.

Table: Likes

Column NameType
user_idint
page_idint
  • (user_id, page_id) is the primary key (combination of columns with unique values) for this table.
  • Each row of this table indicates that user_id likes page_id.

Problem Statement

Write a solution to recommend pages to the user with user_id = 1 using the pages that your friends liked. It should not recommend pages you already liked.

Return result table in any order without duplicates.

The result format is in the following example.

Example 1:

Input:

  • Friendship table:
user1_iduser2_id
12
13
14
23
24
25
61
  • Likes table:
user_idpage_id
188
223
324
456
511
633
277
377
688

Output:

recommended_page
23
24
56
33
77

Explanation:

  • User one is friend with users 2, 3, 4 and 6.
  • Suggested pages are 23 from user 2, 24 from user 3, 56 from user 3 and 33 from user 6.
  • Page 77 is suggested from both user 2 and user 3.
  • Page 88 is not suggested because user 1 already likes it.

Solution

You need to find page recommendations for user_id = 1 using the pages liked by their friends. The recommendations should not include the pages already liked by this user. The problem has three components.

  1. Find pages liked by user_id = 1.
  2. Find friends of user_id = 1.
  3. Find distinct pages liked by these list of friends.

You can find pages liked by user_id = 1 using simple query like this. You will need to exclude this from the list of page recommendations using NOT IN clause.

1SELECT page_id FROM Likes WHERE user_id = 1 

To find friends, you can check either user1_id or user2_id. The friendship can be one way as well.

1SELECT user2_id AS user_id FROM Friendship WHERE user1_id = 1
2UNION
3SELECT user1_id AS user_id FROM Friendship WHERE user2_id = 1

The same query can also be written using CASE WHEN clause.

1SELECT 
2    CASE 
3        WHEN user1_id = 1 THEN user2_id 
4        WHEN user2_id = 1 THEN user1_id 
5        END AS user_id 
6    FROM Friendship
7    WHERE user1_id = 1 OR user2_id = 1
user_id
6
2
3
4

The last part is to find pages liked by above set of users. This you can find using DISTINCT page_id clause.

1SELECT DISTINCT page_id 
2    FROM Likes

The final solution looks like this.

1SELECT DISTINCT page_id AS recommended_page
2    FROM Likes
3    WHERE user_id IN (
4    SELECT user1_id user_id FROM Friendship WHERE user2_id = 1
5        UNION
6        SELECT user2_id user_id FROM Friendship WHERE user1_id = 1
7) AND page_id NOT IN (
8    SELECT page_id FROM Likes WHERE user_id = 1
9)